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Link for the Problem – Merge Two Sorted Lists– LeetCode Problem
Merge Two Sorted Lists– LeetCode Problem
Problem:
You are given the heads of two sorted linked lists list1
and list2
.
Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.
Return the head of the merged linked list.
Example 1:
![Merge Two Sorted Lists LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct] 2](https://assets.leetcode.com/uploads/2020/10/03/merge_ex1.jpg)
Input: list1 = [1,2,4], list2 = [1,3,4] Output: [1,1,2,3,4,4]
Example 2:
Input: list1 = [], list2 = [] Output: []
Example 3:
Input: list1 = [], list2 = [0] Output: [0]
Constraints:
- The number of nodes in both lists is in the range
[0, 50]
. -100 <= Node.val <= 100
- Both
list1
andlist2
are sorted in non-decreasing order.
Merge Two Sorted Lists– LeetCode Solutions
class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1 || !l2) return l1 ? l1 : l2; if (l1->val > l2->val) swap(l1, l2); l1->next = mergeTwoLists(l1->next, l2); return l1; } };
class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { if (l1 == null || l2 == null) return l1 == null ? l2 : l1; if (l1.val > l2.val) { ListNode temp = l1; l1 = l2; l2 = temp; } l1.next = mergeTwoLists(l1.next, l2); return l1; } }
class Solution: def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode: if not l1 or not l2: return l1 if l1 else l2 if l1.val > l2.val: l1, l2 = l2, l1 l1.next = self.mergeTwoLists(l1.next, l2) return l1
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