Mini-Max Sum in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

• It is easy to understand.
• Algorithm is a step-wise representation of a solution to a given problem.
• In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the Problem – Mini-Max Sum – Hacker Rank Solution

Mini-Max Sum – Hacker Rank Solution

Problem:

Given five positive integers, find the minimum and maximum values that can be calculated by summing exactly four of the five integers. Then print the respective minimum and maximum values as a single line of two space-separated long integers.

Example

16 24

Function Description

Complete the miniMaxSum function in the editor below.

miniMaxSum has the following parameter(s):

• arr: an array of  integers

Print

Print two space-separated integers on one line: the minimum sum and the maximum sum of  of  elements.

Input Format

A single line of five space-separated integers.

Constraints

Output Format

Print two space-separated long integers denoting the respective minimum and maximum values that can be calculated by summing exactly four of the five integers. (The output can be greater than a 32 bit integer.)

Sample Input

1 2 3 4 5

Sample Output

10 14

Explanation

Mini-Max Sum – Hacker Rank Solution

public class MiniMaxSum {
	static void miniMaxSum(int[] arr) {
		long min = 0, max = 0, sum = 0;
		min = arr[0];
		max = min;
		sum = min;
		for (int i = 1; i < arr.length; i++) {
			sum += arr[i];
			if (arr[i] < min) {
				min = arr[i];
			}
			if (arr[i] > max) {
				max = arr[i];
			}
		}
		System.out.print((sum - max) + " " + (sum - min));

	}

}