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Hello **Programmers/Coders,** Today we are going to share ** solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python**. At Each Problem with Successful submission with

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In this post, you will find the solution for the **Number of 1 Bits** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Number of 1 Bits– LeetCode Problem

Number of 1 Bits– LeetCode Problem

**Problem:**

Write a function that takes an unsigned integer and returns the number of ‘1’ bits it has (also known as the Hamming weight).

**Note:**

- Note that in some languages, such as Java, there is no unsigned integer type. In this case, the input will be given as a signed integer type. It should not affect your implementation, as the integer’s internal binary representation is the same, whether it is signed or unsigned.
- In Java, the compiler represents the signed integers using 2’s complement notation. Therefore, in
**Example 3**, the input represents the signed integer.`-3`

.

**Example 1:**

Input:n = 00000000000000000000000000001011Output:3Explanation:The input binary string00000000000000000000000000001011has a total of three '1' bits.

**Example 2:**

Input:n = 00000000000000000000000010000000Output:1Explanation:The input binary string00000000000000000000000010000000has a total of one '1' bit.

**Example 3:**

Input:n = 11111111111111111111111111111101Output:31Explanation:The input binary string11111111111111111111111111111101has a total of thirty one '1' bits.

**Constraints:**

- The input must be a
**binary string**of length`32`

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Number of 1 Bits– LeetCode Solutions

Number of 1 BitsSolution in C++:

class Solution { public: int hammingWeight(uint32_t n) { int ans = 0; for (int i = 0; i < 32; ++i) if ((n >> i) & 1) ++ans; return ans; } };

Number of 1 BitsSolution in Java:

public class Solution { // you need to treat n as an unsigned value public int hammingWeight(int n) { int ans = 0; for (int i = 0; i < 32; ++i) if (((n >> i) & 1) == 1) ++ans; return ans; } }

Number of 1 BitsSolution in Python:

class Solution: def hammingWeight(self, n: int) -> int: ans = 0 for i in range(32): if (n >> i) & 1: ans += 1 return ans