Rotate List LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Rotate List in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the Problem – Rotate List– LeetCode Problem

Rotate List– LeetCode Problem

Problem:

Given the head of a linked list, rotate the list to the right by k places.

Example 1:

Input: head = [1,2,3,4,5], k = 2
Output: [4,5,1,2,3]

Example 2:

Input: head = [0,1,2], k = 4
Output: [2,0,1]

Constraints:

• The number of nodes in the list is in the range [0, 500].
• -100 <= Node.val <= 100
• 0 <= k <= 2 * 109

Rotate List– LeetCode Solutions

Rotate List in C++:

class Solution {
 public:
  ListNode* rotateRight(ListNode* head, int k) {
    if (!head || !head->next || k == 0)
      return head;

    ListNode* tail;
    int length = 1;
    for (tail = head; tail->next; tail = tail->next)
      ++length;
    tail->next = head;  // circle the list

    const int t = length - k % length;
    for (int i = 0; i < t; ++i)
      tail = tail->next;
    ListNode* newHead = tail->next;
    tail->next = nullptr;

    return newHead;
  }
};

Rotate List in Java:

class Solution {
  public ListNode rotateRight(ListNode head, int k) {
    if (head == null || head.next == null || k == 0)
      return head;

    int length = 1;
    ListNode tail = head;
    for (; tail.next != null; tail = tail.next)
      ++length;
    tail.next = head; // circle the list

    final int t = length - k % length;
    for (int i = 0; i < t; ++i)
      tail = tail.next;
    ListNode newHead = tail.next;
    tail.next = null;

    return newHead;
  }
}

Rotate List in Python:

class Solution:
  def rotateRight(self, head: ListNode, k: int) -> ListNode:
    if not head or not head.next or k == 0:
      return head

    tail = head
    length = 1
    while tail.next:
      tail = tail.next
      length += 1
    tail.next = head  # circle the list

    t = length - k % length
    for _ in range(t):
      tail = tail.next
    newHead = tail.next
    tail.next = None

    return newHead