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In this post, you will find the solution for the **Set Matrix Zeroes** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Set Matrix Zeroes– LeetCode Problem

Set Matrix Zeroes – LeetCode Problem

**Problem:**

Given an `m x n`

integer matrix `matrix`

, if an element is `0`

, set its entire row and column to `0`

‘s, and return *the matrix*.

You must do it in place.

**Example 1:**

Input:matrix = [[1,1,1],[1,0,1],[1,1,1]]Output:[[1,0,1],[0,0,0],[1,0,1]]

**Example 2:**

Input:matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]Output:[[0,0,0,0],[0,4,5,0],[0,3,1,0]]

**Constraints:**

`m == matrix.length`

`n == matrix[0].length`

`1 <= m, n <= 200`

`-2`

^{31}<= matrix[i][j] <= 2^{31}- 1

Set Matrix Zeroes– LeetCode Solutions

Set Matrix Zeroes in C++:

class Solution { public: void setZeroes(vector<vector<int>>& matrix) { const int m = matrix.size(); const int n = matrix[0].size(); bool shouldFillFirstRow = false; bool shouldFillFirstCol = false; for (int j = 0; j < n; ++j) if (matrix[0][j] == 0) { shouldFillFirstRow = true; break; } for (int i = 0; i < m; ++i) if (matrix[i][0] == 0) { shouldFillFirstCol = true; break; } // store the information in the 1st row/col for (int i = 1; i < m; ++i) for (int j = 1; j < n; ++j) if (matrix[i][j] == 0) { matrix[i][0] = 0; matrix[0][j] = 0; } // fill 0s for the matrix except the 1st row/col for (int i = 1; i < m; ++i) for (int j = 1; j < n; ++j) if (matrix[i][0] == 0 || matrix[0][j] == 0) matrix[i][j] = 0; // fill 0s for the 1st row if needed if (shouldFillFirstRow) for (int j = 0; j < n; ++j) matrix[0][j] = 0; // fill 0s for the 1st col if needed if (shouldFillFirstCol) for (int i = 0; i < m; ++i) matrix[i][0] = 0; } };

Set Matrix Zeroes in Java:

class Solution { public void setZeroes(int[][] matrix) { final int m = matrix.length; final int n = matrix[0].length; boolean shouldFillFirstRow = false; boolean shouldFillFirstCol = false; for (int j = 0; j < n; ++j) if (matrix[0][j] == 0) { shouldFillFirstRow = true; break; } for (int i = 0; i < m; ++i) if (matrix[i][0] == 0) { shouldFillFirstCol = true; break; } // store the information in the 1st row/col for (int i = 1; i < m; ++i) for (int j = 1; j < n; ++j) if (matrix[i][j] == 0) { matrix[i][0] = 0; matrix[0][j] = 0; } // fill 0s for the matrix except the 1st row/col for (int i = 1; i < m; ++i) for (int j = 1; j < n; ++j) if (matrix[i][0] == 0 || matrix[0][j] == 0) matrix[i][j] = 0; // fill 0s for the 1st row if needed if (shouldFillFirstRow) for (int j = 0; j < n; ++j) matrix[0][j] = 0; // fill 0s for the 1st col if needed if (shouldFillFirstCol) for (int i = 0; i < m; ++i) matrix[i][0] = 0; } }

Set Matrix Zeroes in Python:

class Solution: def setZeroes(self, matrix: List[List[int]]) -> None: m = len(matrix) n = len(matrix[0]) shouldFillFirstRow = 0 in matrix[0] shouldFillFirstCol = 0 in list(zip(*matrix))[0] # store the information in the 1st row/col for i in range(1, m): for j in range(1, n): if matrix[i][j] == 0: matrix[i][0] = 0 matrix[0][j] = 0 # fill 0s for the matrix except the 1st row/col for i in range(1, m): for j in range(1, n): if matrix[i][0] == 0 or matrix[0][j] == 0: matrix[i][j] = 0 # fill 0s for the 1st row if needed if shouldFillFirstRow: matrix[0] = [0] * n # fill 0s for the 1st col if needed if shouldFillFirstCol: for row in matrix: row[0] = 0