Sort Colors LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [๐Ÿ’ฏCorrect]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Sort Colors in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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About LeetCode

LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews. 

LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either EasyMedium, or Hard.

LeetCode problems focus on algorithms and data structures. Here is some topic you can find problems on LeetCode:

  • Mathematics/Basic Logical Based Questions
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  • Trees & Graphs
  • Greedy Algorithms
  • Breadth-First Search
  • Depth-First Search
  • Sorting & Searching
  • BST (Binary Search Tree)
  • Database
  • Linked List
  • Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the ProblemSort Colorsโ€“ LeetCode Problem

Sort Colorsโ€“ LeetCode Problem

Problem:

Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.

We will use the integers 01, and 2 to represent the color red, white, and blue, respectively.

You must solve this problem without using the library’s sort function.

Example 1:

Input: nums = [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]

Example 2:

Input: nums = [2,0,1]
Output: [0,1,2]

Constraints:

  • n == nums.length
  • 1 <= n <= 300
  • nums[i] is either 01, or 2.
Sort Colorsโ€“ LeetCode Solutions
Sort Colors in C++:
class Solution {
 public:
  void sortColors(vector<int>& nums) {
    int l = 0;                // next 0 should be put in l
    int r = nums.size() - 1;  // next 2 should be put in r

    for (int i = 0; i <= r;)
      if (nums[i] == 0)
        swap(nums[i++], nums[l++]);
      else if (nums[i] == 1)
        ++i;
      else
        // we may swap a 0 to index i, but we're still not sure whether
        // this 0 is put in the correct index, so we can't move pointer i
        swap(nums[i], nums[r--]);
  }
};
Sort Colors in Java:
class Solution {
  public void sortColors(int[] nums) {
    int l = 0;               // next 0 should be put in l
    int r = nums.length - 1; // next 2 should be put in r

    for (int i = 0; i <= r;)
      if (nums[i] == 0)
        swap(nums, i++, l++);
      else if (nums[i] == 1)
        ++i;
      else
        // we may swap a 0 to index i, but we're still not sure whether
        // this 0 is put in the correct index, so we can't move pointer i
        swap(nums, i, r--);
  }

  private void swap(int[] nums, int i, int j) {
    final int temp = nums[i];
    nums[i] = nums[j];
    nums[j] = temp;
  }
}
Sort Colors in Python:
class Solution:
  def sortColors(self, nums: List[int]) -> None:
    zero = -1
    one = -1
    two = -1

    for num in nums:
      if num == 0:
        two += 1
        one += 1
        zero += 1
        nums[two] = 2
        nums[one] = 1
        nums[zero] = 0
      elif num == 1:
        two += 1
        one += 1
        nums[two] = 2
        nums[one] = 1
      else:
        two += 1
        nums[two] = 2

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