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In this post, you will find the solution for Between Two Sets in Java-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.
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Introduction To Algorithm
The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results.
Advantages of Algorithms:
- It is easy to understand.
- Algorithm is a step-wise representation of a solution to a given problem.
- In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.
Link for the Problem – Between Two Sets – Hacker Rank Solution
Between Two Sets – Hacker Rank Solution
Problem:
There will be two arrays of integers. Determine all integers that satisfy the following two conditions:
- The elements of the first array are all factors of the integer being considered
- The integer being considered is a factor of all elements of the second array
These numbers are referred to as being between the two arrays. Determine how many such numbers exist.
Example
![Between Two Sets in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct] 2 Between Two Sets in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]](https://technorj.com/wp-content/uploads/2021/12/image-48.png)
Function Description
Complete the getTotalX function in the editor below. It should return the number of integers that are betwen the sets.
getTotalX has the following parameter(s):
- int a[n]: an array of integers
- int b[m]: an array of integers
Returns
- int: the number of integers that are between the sets
Input Format
![Between Two Sets in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct] 3 image 49](https://technorj.com/wp-content/uploads/2021/12/image-49.png)
Sample Input
2 3 2 4 16 32 96
Sample Output
3
Explanation
2 and 4 divide evenly into 4, 8, 12 and 16.
4, 8 and 16 divide evenly into 16, 32, 96.
4, 8 and 16 are the only three numbers for which each element of a is a factor and each is a factor of all elements of b.
Between Two Sets – Hacker Rank Solution
import java.util.Scanner; /** * @author Techno-RJ * */ public class BetweenTwoSets { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); int gcd = 0; int a[] = new int[n]; int b[] = new int[m]; for (int i = 0; i < n; i++) { a[i] = sc.nextInt(); } int lcm = a[0]; for (int i = 0; i < m; i++) { b[i] = sc.nextInt(); gcd = findGCD(b[i], gcd); } for (int i = 0; i < n - 1; i++) { lcm = (lcm * a[i + 1]) / findGCD(a[i + 1], lcm); } int count = 0, t = 0; for (int i = 1; i <= gcd && t <= gcd; i++) { t = lcm * i; if (gcd % (lcm * i) == 0) { count++; } } System.out.println(count); sc.close(); } private static int findGCD(int a, int b) { return b == 0 ? a : findGCD(b, a % b); } }
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