Placements SQl in SQL | HackerRank Programming Solutions | HackerRank SQL Solutions

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Introduction To SQL

SQL stands for Structured Query Language. SQL is used to create, remove, alter the database and database objects in a database management system and to store, retrieve, update the data in a database. SQL is a standard language for creating, accessing, manipulating database management system. SQL works for all modern relational database management systems, like SQL Server, Oracle, MySQL, etc.

• It is a standard language for Relational Database System. It enables a user to create, read, update and delete relational databases and tables.
• All the RDBMS like MySQL, Informix, Oracle, MS Access and SQL Server use SQL as their standard database language.
• SQL allows users to query the database in a number of ways, using English-like statements.

Link for the Problem – Placements SQL – Hacker Rank Solution

Placements SQL – Hacker Rank Solution

Problem:

You are given three tables: Students, Friends and Packages. Students contains two columns: ID and Name. Friends contains two columns: ID and Friend_ID (ID of the ONLY best friend). Packages contains two columns: ID and Salary (offered salary in $ thousands per month).

Write a query to output the names of those students whose best friends got offered a higher salary than them. Names must be ordered by the salary amount offered to the best friends. It is guaranteed that no two students got same salary offer.

Sample Input

Sample Output

Samantha
Julia
Scarlet

Explanation

See the following table:

Now,

• Samantha’s best friend got offered a higher salary than her at 11.55
• Julia’s best friend got offered a higher salary than her at 12.12
• Scarlet’s best friend got offered a higher salary than her at 15.2
• Ashley’s best friend did NOT get offered a higher salary than her

The name output, when ordered by the salary offered to their friends, will be:

• Samantha
• Julia
• Scarlet

Placements SQL – Hacker Rank Solution

select temp1.sn
from (select S.ID si,S.Name sn,P.Salary ps from Students S join Packages P on S.ID=P.ID) temp1 join (select FF.ID fi,FF.Friend_ID fd,PP.Salary 
pps from Friends FF join Packages PP on FF.Friend_ID=pp.ID) temp2 on temp1.si=temp2.fi and temp1.ps<temp2.pps
order by temp2.pps asc;