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In this post, you will find the solution for the **Rotate Array** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Rotate Array– LeetCode Problem

Rotate Array– LeetCode Problem

**Problem:**

Given an array, rotate the array to the right by `k`

steps, where `k`

is non-negative.

**Example 1:**

Input:nums = [1,2,3,4,5,6,7], k = 3Output:[5,6,7,1,2,3,4]Explanation:rotate 1 steps to the right: [7,1,2,3,4,5,6] rotate 2 steps to the right: [6,7,1,2,3,4,5] rotate 3 steps to the right: [5,6,7,1,2,3,4]

**Example 2:**

Input:nums = [-1,-100,3,99], k = 2Output:[3,99,-1,-100]Explanation:rotate 1 steps to the right: [99,-1,-100,3] rotate 2 steps to the right: [3,99,-1,-100]

**Constraints:**

`1 <= nums.length <= 10`

^{5}`-2`

^{31}<= nums[i] <= 2^{31}- 1`0 <= k <= 10`

^{5}

Rotate Array– LeetCode Solutions

Rotate ArraySolution in C++:

class Solution { public: void rotate(vector<int>& nums, int k) { k %= nums.size(); reverse(nums, 0, nums.size() - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.size() - 1); } private: void reverse(vector<int>& nums, int l, int r) { while (l < r) swap(nums[l++], nums[r--]); } };

Rotate Array Solution in Java:

class Solution { public void rotate(int[] nums, int k) { k %= nums.length; reverse(nums, 0, nums.length - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.length - 1); } private void reverse(int[] nums, int l, int r) { while (l < r) swap(nums, l++, r--); } private void swap(int[] nums, int l, int r) { final int temp = nums[l]; nums[l] = nums[r]; nums[r] = temp; } }

Rotate ArraySolution in Python:

class Solution: def rotate(self, nums: List[int], k: int) -> None: k %= len(nums) self.reverse(nums, 0, len(nums) - 1) self.reverse(nums, 0, k - 1) self.reverse(nums, k, len(nums) - 1) def reverse(self, nums: List[int], l: int, r: int) -> None: while l < r: nums[l], nums[r] = nums[r], nums[l] l += 1 r -= 1