Container With Most Water LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Problems C++

Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Container With Most Water in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

Use “Ctrl+F” To Find Any Questions Answer. & For Mobile User, You Just Need To Click On Three dots In Your Browser & You Will Get A “Find” Option There. Use These Option to Get Any Random Questions Answer.

About LeetCode

LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews. 

LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either Easy, Medium, or Hard.

LeetCode problems focus on algorithms and data structures. Here is some topic you can find problems on LeetCode:

• Mathematics/Basic Logical Based Questions
• Arrays
• Strings
• Hash Table
• Dynamic Programming
• Stack & Queue
• Trees & Graphs
• Greedy Algorithms
• Breadth-First Search
• Depth-First Search
• Sorting & Searching
• BST (Binary Search Tree)
• Database
• Linked List
• Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the Problem – Container With Most Water– LeetCode Problem

Container With Most Water– LeetCode Problem

Problem:

You are given an integer array height of length n. There are n vertical lines are drawn such that the two endpoints of the ith line is (i, 0) and (i, height[i]).

Find two lines that together with the x-axis form a container, such that the container contains the most water.

Return the maximum amount of water a container can store.

Notice that you may not slant the container.

Example 1:

Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.

Example 2:

Input: height = [1,1]
Output: 1

Constraints:

• n == height.length
• 2 <= n <= 105
• 0 <= height[i] <= 104

Container With Most Water– LeetCode Solutions

class Solution {
 public:
  int maxArea(vector<int>& height) {
    int ans = 0;
    int l = 0;
    int r = height.size() - 1;

    while (l < r) {
      const int minHeight = min(height[l], height[r]);
      ans = max(ans, minHeight * (r - l));
      if (height[l] < height[r])
        ++l;
      else
        --r;
    }

    return ans;
  }
};

class Solution {
  public int maxArea(int[] height) {
    int ans = 0;
    int l = 0;
    int r = height.length - 1;

    while (l < r) {
      final int minHeight = Math.min(height[l], height[r]);
      ans = Math.max(ans, minHeight * (r - l));
      if (height[l] < height[r])
        ++l;
      else
        --r;
    }

    return ans;
  }
}

class Solution:
  def maxArea(self, height: List[int]) -> int:
    ans = 0
    l = 0
    r = len(height) - 1

    while l < r:
      minHeight = min(height[l], height[r])
      ans = max(ans, minHeight * (r - l))
      if height[l] < height[r]:
        l += 1
      else:
        r -= 1

    return ans