The Full Counting Sort in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

• It is easy to understand.
• Algorithm is a step-wise representation of a solution to a given problem.
• In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the Problem – The Full Counting Sort– Hacker Rank Solution

The Full Counting Sort– Hacker Rank Solution

Problem:

Use the counting sort to order a list of strings associated with integers. If two strings are associated with the same integer, they must be printed in their original order, i.e. your sorting algorithm should be stable. There is one other twist: strings in the first half of the array are to be replaced with the character - (dash, ascii 45 decimal).

Insertion Sort and the simple version of Quicksort are stable, but the faster in-place version of Quicksort is not since it scrambles around elements while sorting.

Design your counting sort to be stable.

Example

The first two strings are replaced with ‘-‘. Since the maximum associated integer is , set up a helper array with at least two empty arrays as elements. The following shows the insertions into an array of three empty arrays.

i	string	converted	list
0				[[],[],[]]
1 	a 	-		[[-],[],[]]
2	b	-		[[-],[-],[]]
3	c			[[-,c],[-],[]]
4	d			[[-,c],[-,d],[]]

The result is then printed:  .

Function Description

Complete the countSort function in the editor below. It should construct and print the sorted strings.

countSort has the following parameter(s):

• string arr[n][2]: each arr[i] is comprised of two strings, x and s

Returns
– Print the finished array with each element separated by a single space.

Note: The first element of each , , must be cast as an integer to perform the sort.

Input Format

The first line contains , the number of integer/string pairs in the array .
Each of the next  contains  and , the integers (as strings) with their associated strings.

Constraints

 is even


 consists of characters in the range 

Output Format

Print the strings in their correct order, space-separated on one line.

Sample Input

20
0 ab
6 cd
0 ef
6 gh
4 ij
0 ab
6 cd
0 ef
6 gh
0 ij
4 that
3 be
0 to
1 be
5 question
1 or
2 not
4 is
2 to
4 the

Sample Output

- - - - - to be or not to be - that is the question - - - -

Explanation

The correct order is shown below. In the array at the bottom, strings from the first half of the original array were replaced with dashes.

0 ab
0 ef
0 ab
0 ef
0 ij
0 to
1 be
1 or
2 not
2 to
3 be
4 ij
4 that
4 is
4 the
5 question
6 cd
6 gh
6 cd
6 gh

sorted = [['-', '-', '-', '-', '-', 'to'], ['be', 'or'], ['not', 'to'], ['be'], ['-', 'that', 'is', 'the'], ['question'], ['-', '-', '-', '-'], [], [], [], []]

The Full Counting Sort – Hacker Rank Solution

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {
    public static void main(String[] args) throws Exception {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(in.readLine());
        StringBuffer[] map = new StringBuffer[100];
        for(int i = 0; i < 100; i++) {
            map[i] = new StringBuffer();
        }
        for(int i = 0; i < n; i++) {
            StringTokenizer tok = new StringTokenizer(in.readLine());
            int v = Integer.parseInt(tok.nextToken());
            String s = tok.nextToken();
            map[v].append(i < n / 2 ? "-" : s).append(" ");
        }
        for(int i = 0; i < 100; i++) {
            System.out.print(map[i]);
        }
        System.out.println();
    }
}