The Report SQL | Hackerrank Solution
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Introduction To SQL
SQL stands for Structured Query Language. SQL is used to create, remove, alter the database and database objects in a database management system and to store, retrieve, update the data in a database. SQL is a standard language for creating, accessing, manipulating database management system. SQL works for all modern relational database management systems, like SQL Server, Oracle, MySQL, etc.
- It is a standard language for Relational Database System. It enables a user to create, read, update and delete relational databases and tables.
- All the RDBMS like MySQL, Informix, Oracle, MS Access and SQL Server use SQL as their standard database language.
- SQL allows users to query the database in a number of ways, using English-like statements.
Link for the Problem – The Report SQL – Hacker Rank Solution
The Report SQL – Hacker Rank Solution
Problem:
You are given two tables: Students and Grades. Students contains three columns ID, Name and Marks.

Grades contains the following data:

Ketty gives Eve a task to generate a report containing three columns: Name, Grade and Mark. Ketty doesn’t want the NAMES of those students who received a grade lower than 8. The report must be in descending order by grade — i.e. higher grades are entered first. If there is more than one student with the same grade (8-10) assigned to them, order those particular students by their name alphabetically. Finally, if the grade is lower than 8, use “NULL” as their name and list them by their grades in descending order. If there is more than one student with the same grade (1-7) assigned to them, order those particular students by their marks in ascending order.
Write a query to help Eve.
Sample Input

Sample Output
Maria 10 99 Jane 9 81 Julia 9 88 Scarlet 8 78 NULL 7 63 NULL 7 68
Note
Print “NULL” as the name if the grade is less than 8.
Explanation
Consider the following table with the grades assigned to the students:

So, the following students got 8, 9 or 10 grades:
- Maria (grade 10)
- Jane (grade 9)
- Julia (grade 9)
- Scarlet (grade 8)
The Report SQL – Hacker Rank Solution
SELECT IF(g.Grade<8, NULL, s.Name), g.Grade, s.Marks FROM Students AS s JOIN Grades AS g ON s.Marks BETWEEN g.Min_Mark AND g.Max_Mark ORDER BY g.Grade DESC, s.Name, s.Marks;
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