Top Earners in SQL | HackerRank Programming Solutions | HackerRank SQL Solutions

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Introduction To SQL

SQL stands for Structured Query Language. SQL is used to create, remove, alter the database and database objects in a database management system and to store, retrieve, update the data in a database. SQL is a standard language for creating, accessing, manipulating database management system. SQL works for all modern relational database management systems, like SQL Server, Oracle, MySQL, etc.

• It is a standard language for Relational Database System. It enables a user to create, read, update and delete relational databases and tables.
• All the RDBMS like MySQL, Informix, Oracle, MS Access and SQL Server use SQL as their standard database language.
• SQL allows users to query the database in a number of ways, using English-like statements.

Link for the Problem – Top Earners sql – Hacker Rank Solution

Top Earners sql – Hacker Rank Solution

Problem:

We define an employee’s total earnings to be their monthly  worked, and the maximum total earnings to be the maximum total earnings for any employee in the Employee table. Write a query to find the maximum total earnings for all employees as well as the total number of employees who have maximum total earnings. Then print these values as  space-separated integers.

Input Format

The Employee table containing employee data for a company is described as follows:

where employee_id is an employee’s ID number, name is their name, months is the total number of months they’ve been working for the company, and salary is the their monthly salary.

Sample Input

Sample Output

69952 1

Explanation

The table and earnings data is depicted in the following diagram:4

The maximum earnings value is . The only employee with earnings  is Kimberly, so we print the maximum earnings value () and a count of the number of employees who have earned  (which is ) as two space-separated values.

Top Earners sql – Hacker Rank Solution

SELECT MAX(SALARY*MONTHS), COUNT(*)
FROM EMPLOYEE
WHERE (SALARY*MONTHS) = (SELECT MAX(SALARY*MONTHS)
                         FROM EMPLOYEE);