Diagonal Difference in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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Algorithm Solution in Hackerrank | Java Hackerrank Solutions

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In this post, you will find the solution for Diagonal Difference in Java-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

  • It is easy to understand.
  • Algorithm is a step-wise representation of a solution to a given problem.
  • In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the Problem – Diagonal Difference– Hacker Rank Solution

Diagonal Difference – Hacker Rank Solution

Problem:

Given a square matrix, calculate the absolute difference between the sums of its diagonals.

For example, the square matrix  is shown below:

1 2 3
4 5 6
9 8 9
image 39

Return

  • int: the absolute diagonal difference

Input Format

image 40

Output Format

Return the absolute difference between the sums of the matrix’s two diagonals as a single integer.

Sample Input

3
11 2 4
4 5 6
10 8 -12

Sample Output

15

Explanation

The primary diagonal is:

11
   5
     -12

Sum across the primary diagonal: 11 + 5 – 12 = 4

The secondary diagonal is:

     4
   5
10

Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 – 19| = 15

Note: |x| is the absolute value of x

Diagonal Difference – Hacker Rank Solution
public class DiagonalDifference {
	
	static int diagonalDifference(int[][] arr) {
		int leftSum = 0, rightSum = 0;
		int n = arr.length;
		for (int i = 0; i < n; i++) {
			leftSum += arr[i][i];
			rightSum += arr[i][n - 1 - i];
		}
		return (Math.abs(leftSum - rightSum));
	}
}

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