Divisible Sum Pairs in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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Algorithm Solution in Hackerrank | Java Hackerrank Solutions

Hello Programmers/Coders, Today we are going to share solutions of Programming problems of HackerRank, Algorithm Solutions of Problem Solving Section in Java. At Each Problem with Successful submission with all Test Cases Passed, you will get an score or marks. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for Divisible Sum Pairs in Java-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

  • It is easy to understand.
  • Algorithm is a step-wise representation of a solution to a given problem.
  • In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the Problem – Divisible Sum Pairs– Hacker Rank Solution 

Divisible Sum Pairs – Hacker Rank Solution

Problem:

image 56

Function Description

Complete the divisibleSumPairs function in the editor below.

divisibleSumPairs has the following parameter(s):

  • int n: the length of array 
  • int ar[n]: an array of integers
  • int k: the integer divisor

Returns
– int: the number of pairs

Input Format

The first line contains 2 space-separated integers, n and k.
The second line contains n space-separated integers, each a value of arr[i].

Constraints

image 57

Sample Input

STDIN           Function
-----           --------
6 3             n = 6, k = 3
1 3 2 6 1 2     ar = [1, 3, 2, 6, 1, 2]

Sample Output

 5

Explanation

image 58
Divisible Sum Pairs – Hacker Rank Solution
import java.util.Scanner;

/**
 * @author Techno-RJ
 *
 */
public class DivisibleSumPairs {

	static int divisibleSumPairs(int n, int k, int[] ar) {
		int[] bucket = new int[k];
		int pairCounter = 0;

		for (int element : ar) {

			int remainder = element % k;
			int complement = (k-remainder)%k;
			pairCounter += ar[complement];
			bucket[remainder]++;

		}
		return pairCounter;
	}

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();

		int k = sc.nextInt();
		int a[] = new int[n];
		for (int i = 0; i < n; i++) {
			a[i] = sc.nextInt();
		}
//		int count = 0;
//		for (int i = 0; i < M; i++) {
//			for (int j = i + 1; j < M; j++) {
//				if ((a[i] + a[j]) % N == 0) {
//					count++;
//				}
//			}
//		}
		int count = divisibleSumPairs(n, k, a);
		System.out.println(count);
		sc.close();
	}

}

110 thoughts on “Divisible Sum Pairs in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]”

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