Migratory Birds in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

• It is easy to understand.
• Algorithm is a step-wise representation of a solution to a given problem.
• In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the Problem – Migratory Birds – Hacker Rank Solution

Migratory Birds– Hacker Rank Solution

Problem:

Given an array of bird sightings where every element represents a bird type id, determine the id of the most frequently sighted type. If more than 1 type has been spotted that maximum amount, return the smallest of their ids.

Example

Function Description

Complete the migratoryBirds function in the editor below.

migratoryBirds has the following parameter(s):

• int arr[n]: the types of birds sighted

Returns

• int: the lowest type id of the most frequently sighted birds

Input Format

The first line contains an integer, , the size of .
The second line describes  as  space-separated integers, each a type number of the bird sighted.

Constraints

Sample Input 0

6
1 4 4 4 5 3

Sample Output 0

4

Explanation 0

The different types of birds occur in the following frequencies:

• Type :  bird
• Type :  birds
• Type :  bird
• Type :  birds
• Type :  bird

The type number that occurs at the highest frequency is type , so we print  as our answer.

Sample Input 1

11
1 2 3 4 5 4 3 2 1 3 4

Sample Output 1

3

Explanation 1

The different types of birds occur in the following frequencies:

Migratory Birds – Hacker Rank Solution

import java.util.Scanner;

/**
 * @author Techno-RJ
 *
 */
public class MigratoryBirds {
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int n = in.nextInt();
		int[] types = new int[n];
		int maxFreqValue = 0, freqId = 0;
		for (int types_i = 0; types_i < n; types_i++) {
			int index = in.nextInt();
			types[index - 1]++;
		}

		for (int i = 0; i < n; i++) {
			if (types[i] > maxFreqValue) {
				maxFreqValue = types[i];
				freqId = i + 1;
			}
		}
		System.out.println(freqId);
		in.close();
	}
}