Dungeon Game LeetCode Programming Solutions 2022 | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

Dungeon Game LeetCode Solution | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Solutions in C++

Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Dungeon Game in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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About LeetCode

LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews. 

LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either EasyMedium, or Hard.

LeetCode problems focus on algorithms and data structures. Here is some topic you can find problems on LeetCode:

  • Mathematics/Basic Logical Based Questions
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  • Dynamic Programming
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  • Trees & Graphs
  • Greedy Algorithms
  • Breadth-First Search
  • Depth-First Search
  • Sorting & Searching
  • BST (Binary Search Tree)
  • Database
  • Linked List
  • Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the ProblemDungeon Game– LeetCode Problem

Dungeon Game– LeetCode Problem

Problem:

The demons had captured the princess and imprisoned her in the bottom-right corner of a dungeon. The dungeon consists of m x n rooms laid out in a 2D grid. Our valiant knight was initially positioned in the top-left room and must fight his way through dungeon to rescue the princess.

The knight has an initial health point represented by a positive integer. If at any point his health point drops to 0 or below, he dies immediately.

Some of the rooms are guarded by demons (represented by negative integers), so the knight loses health upon entering these rooms; other rooms are either empty (represented as 0) or contain magic orbs that increase the knight’s health (represented by positive integers).

To reach the princess as quickly as possible, the knight decides to move only rightward or downward in each step.

Return the knight’s minimum initial health so that he can rescue the princess.

Note that any room can contain threats or power-ups, even the first room the knight enters and the bottom-right room where the princess is imprisoned.

Example 1:

dungeon grid 1
Input: dungeon = [[-2,-3,3],[-5,-10,1],[10,30,-5]]
Output: 7
Explanation: The initial health of the knight must be at least 7 if he follows the optimal path: RIGHT-> RIGHT -> DOWN -> DOWN.

Example 2:

Input: dungeon = [[0]]
Output: 1

Constraints:

  • m == dungeon.length
  • n == dungeon[i].length
  • 1 <= m, n <= 200
  • -1000 <= dungeon[i][j] <= 1000
Dungeon Game– LeetCode Solutions
Dungeon Game Solution in C++:
class Solution {
 public:
  int calculateMinimumHP(vector<vector<int>>& dungeon) {
    const int m = dungeon.size();
    const int n = dungeon[0].size();
    vector<vector<int>> dp(m + 1, vector<int>(n + 1, INT_MAX));
    dp[m][n - 1] = 1;
    dp[m - 1][n] = 1;

    for (int i = m - 1; i >= 0; --i)
      for (int j = n - 1; j >= 0; --j) {
        dp[i][j] = min(dp[i + 1][j], dp[i][j + 1]) - dungeon[i][j];
        dp[i][j] = max(dp[i][j], 1);
      }

    return dp[0][0];
  }
};
Dungeon Game Solution in Java:
class Solution {
  public int calculateMinimumHP(int[][] dungeon) {
    final int m = dungeon.length;
    final int n = dungeon[0].length;
    int[][] dp = new int[m + 1][n + 1];
    Arrays.stream(dp).forEach(A -> Arrays.fill(A, Integer.MAX_VALUE));
    dp[m][n - 1] = 1;
    dp[m - 1][n] = 1;

    for (int i = m - 1; i >= 0; --i)
      for (int j = n - 1; j >= 0; --j) {
        dp[i][j] = Math.min(dp[i + 1][j], dp[i][j + 1]) - dungeon[i][j];
        dp[i][j] = Math.max(dp[i][j], 1);
      }

    return dp[0][0];
  }
}
Dungeon Game Solution in Python:
class Solution:
  def calculateMinimumHP(self, dungeon: List[List[int]]) -> int:
    m = len(dungeon)
    n = len(dungeon[0])
    dp = [math.inf] * (n + 1)
    dp[n - 1] = 1

    for i in reversed(range(m)):
      for j in reversed(range(n)):
        dp[j] = min(dp[j], dp[j + 1]) - dungeon[i][j]
        dp[j] = max(dp[j], 1)

    return dp[0]
  • Time: O(mn)O(mn)
  • Space: O(mn) \to O(n)O(mn)→O(n)

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