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In this post, you will find the solution for the **Find First and Last Position of Element in Sorted Array** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Find First and Last Position of Element in Sorted Array– LeetCode Problem

Find First and Last Position of Element in Sorted Array– LeetCode Problem

**Problem:**

Given an array of integers `nums`

sorted in non-decreasing order, find the starting and ending position of a given `target`

value.

If `target`

is not found in the array, return `[-1, -1]`

.

You must write an algorithm with `O(log n)`

runtime complexity.

**Example 1:**

Input:nums = [5,7,7,8,8,10], target = 8Output:[3,4]

**Example 2:**

Input:nums = [5,7,7,8,8,10], target = 6Output:[-1,-1]

**Example 3:**

Input:nums = [], target = 0Output:[-1,-1]

**Constraints:**

`0 <= nums.length <= 10`

^{5}`-10`

^{9}<= nums[i] <= 10^{9}`nums`

is a non-decreasing array.`-10`

^{9}<= target <= 10^{9}

Find First and Last Position of Element in Sorted Array– LeetCode Solutions

class Solution { public: vector<int> searchRange(vector<int>& nums, int target) { const int l = lower_bound(begin(nums), end(nums), target) - begin(nums); if (l == nums.size() || nums[l] != target) return {-1, -1}; const int r = upper_bound(begin(nums), end(nums), target) - begin(nums) - 1; return {l, r}; } };

class Solution { public int[] searchRange(int[] nums, int target) { final int l = firstGreaterEqual(nums, target); if (l == nums.length || nums[l] != target) return new int[] {-1, -1}; final int r = firstGreaterEqual(nums, target + 1) - 1; return new int[] {l, r}; } // find the first index l s.t A[l] >= target // return A.length if can't find private int firstGreaterEqual(int[] A, int target) { int l = 0; int r = A.length; while (l < r) { final int m = l + (r - l) / 2; if (A[m] >= target) r = m; else l = m + 1; } return l; } }

class Solution: def searchRange(self, nums: List[int], target: int) -> List[int]: l = bisect_left(nums, target) if l == len(nums) or nums[l] != target: return -1, -1 r = bisect_right(nums, target) - 1 return l, r