Search Insert Position LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Search Insert Position in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either Easy, Medium, or Hard.

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• Mathematics/Basic Logical Based Questions
• Arrays
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• Stack & Queue
• Trees & Graphs
• Greedy Algorithms
• Breadth-First Search
• Depth-First Search
• Sorting & Searching
• BST (Binary Search Tree)
• Database
• Linked List
• Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the Problem – Search Insert Position– LeetCode Problem

Search Insert Position – LeetCode Problem

Problem:

Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with O(log n) runtime complexity.

Example 1:

Input: nums = [1,3,5,6], target = 5
Output: 2

Example 2:

Input: nums = [1,3,5,6], target = 2
Output: 1

Example 3:

Input: nums = [1,3,5,6], target = 7
Output: 4

Constraints:

• 1 <= nums.length <= 104
• -104 <= nums[i] <= 104
• nums contains distinct values sorted in ascending order.
• -104 <= target <= 104

Search Insert Position– LeetCode Solutions

class Solution {
 public:
  int searchInsert(vector<int>& nums, int target) {
    int l = 0;
    int r = nums.size();

    while (l < r) {
      const int m = l + (r - l) / 2;
      if (nums[m] == target)
        return m;
      if (nums[m] < target)
        l = m + 1;
      else
        r = m;
    }

    return l;
  }
};

class Solution {
  public int searchInsert(int[] nums, int target) {
    int l = 0;
    int r = nums.length;

    while (l < r) {
      final int m = l + (r - l) / 2;
      if (nums[m] == target)
        return m;
      if (nums[m] < target)
        l = m + 1;
      else
        r = m;
    }

    return l;
  }
}

class Solution:
  def searchInsert(self, nums: List[int], target: int) -> int:
    l = 0
    r = len(nums)

    while l < r:
      m = (l + r) // 2
      if nums[m] == target:
        return m
      if nums[m] < target:
        l = m + 1
      else:
        r = m

    return l