Forming a Magic Square in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

  • It is easy to understand.
  • Algorithm is a step-wise representation of a solution to a given problem.
  • In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the ProblemForming a Magic Square – Hacker Rank Solution

Forming a Magic Square – Hacker Rank Solution

Problem:

We define a magic square to be an  matrix of distinct positive integers from  to  where the sum of any row, column, or diagonal of length  is always equal to the same number: the magic constant.

You will be given a  matrix  of integers in the inclusive range . We can convert any digit  to any other digit  in the range  at cost of . Given , convert it into a magic square at minimal cost. Print this cost on a new line.

Note: The resulting magic square must contain distinct integers in the inclusive range .

Example

$s = [[5, 3, 4], [1, 5, 8], [6, 4, 2]]

The matrix looks like this:

5 3 4
1 5 8
6 4 2

We can convert it to the following magic square:

8 3 4
1 5 9
6 7 2

This took three replacements at a cost of .

Function Description

Complete the formingMagicSquare function in the editor below.

formingMagicSquare has the following parameter(s):

  • int s[3][3]: a  array of integers

Returns

  • int: the minimal total cost of converting the input square to a magic square

Input Format

Each of the  lines contains three space-separated integers of row .

Constraints

Sample Input 0

4 9 2
3 5 7
8 1 5

Sample Output 0

1

Explanation 0

If we change the bottom right value, , from  to  at a cost of ,  becomes a magic square at the minimum possible cost.

Sample Input 1

4 8 2
4 5 7
6 1 6

Sample Output 1

4

Explanation 1

image 69
Forming a Magic Square – Hacker Rank Solution
import java.util.Scanner;

/**
 * @author Techno-RJ
 *
 */
public class FormingAMagicSquare {
	 static int formingMagicSquare(int[][] s) {
	       int[][][] magicSquareCombinations={ {{4,9,2},{3,5,7},{8,1,6}},
	    		   																			  {{8,3,4},{1,5,9},{6,7,2}},
	    		   																			  {{6,1,8},{7,5,3},{2,9,4}},
	    		   																			  {{2,7,6},{9,5,1},{4,3,8}},
	    		   																			  {{2,9,4},{7,5,3},{6,1,8}},
	    		   																			  {{8,1,6},{3,5,7},{4,9,2}},
	    		   																			  {{6,7,2},{1,5,9},{8,3,4}},
	    		   																			  {{4,3,8},{9,5,1},{2,7,6}}};
		int minCost = Integer.MAX_VALUE;
		for (int i = 0; i < magicSquareCombinations.length; i++) {
			int modifyCost = 0;
			for (int j = 0; j < 3; j++) {
				for (int k = 0; k < 3; k++) {
					modifyCost += Math.abs(s[j][k] - magicSquareCombinations[i][j][k]);
				}
			}
			minCost = Math.min(modifyCost, minCost);
		}
		return minCost;
	}
	    public static void main(String[] args) {
	        Scanner in = new Scanner(System.in);
	        int[][] s = new int[3][3];
	        for(int s_i = 0; s_i < 3; s_i++){
	            for(int s_j = 0; s_j < 3; s_j++){
	                s[s_i][s_j] = in.nextInt();
	            }
	        }
	        int result = formingMagicSquare(s);
	        System.out.println(result);
	        in.close();
	    }
	}

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