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In this post, you will find the solution for **Forming a Magic Square** **in Java-HackerRank Problem**. We are providing the **correct and tested solutions** of coding problems present on **HackerRank**. If you are not able to solve any problem, then you can take help from our Blog/website.

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**Introduction To Algorithm**

The word **Algorithm** means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results.

**Advantages of Algorithms:**

- It is easy to understand.
- Algorithm is a step-wise representation of a solution to a given problem.
- In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

** Link for the Problem** – Forming a Magic Square – Hacker Rank Solution

Forming a Magic Square – Hacker Rank Solution

**Problem:**

We define a magic square to be an matrix of distinct positive integers from to where the sum of any row, column, or diagonal of length is always equal to the same number: the *magic constant*.

You will be given a matrix of integers in the inclusive range . We can convert any digit to any other digit in the range at cost of . Given , convert it into a magic square at *minimal* cost. Print this cost on a new line.

**Note:** The resulting magic square must contain distinct integers in the inclusive range .

**Example**

$s = [[5, 3, 4], [1, 5, 8], [6, 4, 2]]

The matrix looks like this:

5 3 4 1 5 8 6 4 2

We can convert it to the following magic square:

8 3 4 1 5 9 6 7 2

This took three replacements at a cost of .

**Function Description**

Complete the *formingMagicSquare* function in the editor below.

formingMagicSquare has the following parameter(s):

*int s[3][3]:*a array of integers

**Returns**

*int:*the minimal total cost of converting the input square to a magic square

**Input Format**

Each of the lines contains three space-separated integers of row .

**Constraints**

**Sample Input 0**

4 9 2 3 5 7 8 1 5

**Sample Output 0**

1

**Explanation 0**

If we change the bottom right value, , from to at a cost of , becomes a magic square at the minimum possible cost.

**Sample Input 1**

4 8 2 4 5 7 6 1 6

**Sample Output 1**

4

**Explanation 1**

Forming a Magic Square – Hacker Rank Solution

import java.util.Scanner; /** * @author Techno-RJ * */ public class FormingAMagicSquare { static int formingMagicSquare(int[][] s) { int[][][] magicSquareCombinations={ {{4,9,2},{3,5,7},{8,1,6}}, {{8,3,4},{1,5,9},{6,7,2}}, {{6,1,8},{7,5,3},{2,9,4}}, {{2,7,6},{9,5,1},{4,3,8}}, {{2,9,4},{7,5,3},{6,1,8}}, {{8,1,6},{3,5,7},{4,9,2}}, {{6,7,2},{1,5,9},{8,3,4}}, {{4,3,8},{9,5,1},{2,7,6}}}; int minCost = Integer.MAX_VALUE; for (int i = 0; i < magicSquareCombinations.length; i++) { int modifyCost = 0; for (int j = 0; j < 3; j++) { for (int k = 0; k < 3; k++) { modifyCost += Math.abs(s[j][k] - magicSquareCombinations[i][j][k]); } } minCost = Math.min(modifyCost, minCost); } return minCost; } public static void main(String[] args) { Scanner in = new Scanner(System.in); int[][] s = new int[3][3]; for(int s_i = 0; s_i < 3; s_i++){ for(int s_j = 0; s_j < 3; s_j++){ s[s_i][s_j] = in.nextInt(); } } int result = formingMagicSquare(s); System.out.println(result); in.close(); } }

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