Jump Game II LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Jump Game II in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the Problem – Jump Game II– LeetCode Problem 

Jump Game II– LeetCode Problem

Problem:

Given an array of non-negative integers nums, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Your goal is to reach the last index in the minimum number of jumps.

You can assume that you can always reach the last index.

Example 1:

Input: nums = [2,3,1,1,4]
Output: 2
Explanation: The minimum number of jumps to reach the last index is 2. Jump 1 step from index 0 to 1, then 3 steps to the last index.

Example 2:

Input: nums = [2,3,0,1,4]
Output: 2

Constraints:

  • 1 <= nums.length <= 104
  • 0 <= nums[i] <= 1000
Jump Game II– LeetCode Solutions
Jump Game II in C++
class Solution {
 public:
  int jump(vector<int>& nums) {
    int ans = 0;
    int end = 0;
    int farthest = 0;

    for (int i = 0; i < nums.size() - 1; ++i) {
      farthest = max(farthest, i + nums[i]);
      if (farthest >= nums.size() - 1) {
        ++ans;
        break;
      }
      if (i == end) {
        ++ans;
        end = farthest;
      }
    }

    return ans;
  }
};
Jump Game II in Java
class Solution {
  public int jump(int[] nums) {
    int ans = 0;
    int end = 0;
    int farthest = 0;

    for (int i = 0; i < nums.length - 1; ++i) {
      farthest = Math.max(farthest, i + nums[i]);
      if (farthest >= nums.length - 1) {
        ++ans;
        break;
      }
      if (i == end) {
        ++ans;
        end = farthest;
      }
    }

    return ans;
  }
}
Jump Game II in Python
class Solution:
  def jump(self, nums: List[int]) -> int:
    ans = 0
    end = 0
    farthest = 0

    for i in range(len(nums) - 1):
      farthest = max(farthest, i + nums[i])
      if farthest >= len(nums) - 1:
        ans += 1
        break
      if i == end:
        ans += 1
        end = farthest

    return ans

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