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In this post, you will find the solution for the Jump Game II in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.
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Link for the Problem – Jump Game II– LeetCode Problem
Jump Game II– LeetCode Problem
Problem:
Given an array of non-negative integers nums
, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Your goal is to reach the last index in the minimum number of jumps.
You can assume that you can always reach the last index.
Example 1:
Input: nums = [2,3,1,1,4] Output: 2 Explanation: The minimum number of jumps to reach the last index is 2. Jump 1 step from index 0 to 1, then 3 steps to the last index.
Example 2:
Input: nums = [2,3,0,1,4] Output: 2
Constraints:
1 <= nums.length <= 104
0 <= nums[i] <= 1000
Jump Game II– LeetCode Solutions
Jump Game II in C++
class Solution { public: int jump(vector<int>& nums) { int ans = 0; int end = 0; int farthest = 0; for (int i = 0; i < nums.size() - 1; ++i) { farthest = max(farthest, i + nums[i]); if (farthest >= nums.size() - 1) { ++ans; break; } if (i == end) { ++ans; end = farthest; } } return ans; } };
Jump Game II in Java
class Solution { public int jump(int[] nums) { int ans = 0; int end = 0; int farthest = 0; for (int i = 0; i < nums.length - 1; ++i) { farthest = Math.max(farthest, i + nums[i]); if (farthest >= nums.length - 1) { ++ans; break; } if (i == end) { ++ans; end = farthest; } } return ans; } }
Jump Game II in Python
class Solution: def jump(self, nums: List[int]) -> int: ans = 0 end = 0 farthest = 0 for i in range(len(nums) - 1): farthest = max(farthest, i + nums[i]) if farthest >= len(nums) - 1: ans += 1 break if i == end: ans += 1 end = farthest return ans
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