**LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Problems C++**

Hello **Programmers/Coders,** Today we are going to share ** solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python**. At Each Problem with Successful submission with

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In this post, you will find the solution for the **Permutations in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Permutations– LeetCode Problem

Permutations– LeetCode Problem

**Problem:**

Given an array `nums`

of distinct integers, return *all the possible permutations*. You can return the answer in **any order**.

**Example 1:**

Input:nums = [1,2,3]Output:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]

**Example 2:**

Input:nums = [0,1]Output:[[0,1],[1,0]]

**Example 3:**

Input:nums = [1]Output:[[1]]

**Constraints:**

`1 <= nums.length <= 6`

`-10 <= nums[i] <= 10`

- All the integers of
`nums`

are**unique**.

Permutations – LeetCode Solutions

Permutations in C++:

class Solution { public: vector<vector<int>> permute(vector<int>& nums) { vector<vector<int>> ans; dfs(nums, vector<bool>(nums.size()), {}, ans); return ans; } private: void dfs(const vector<int>& nums, vector<bool>&& used, vector<int>&& path, vector<vector<int>>& ans) { if (path.size() == nums.size()) { ans.push_back(path); return; } for (int i = 0; i < nums.size(); ++i) { if (used[i]) continue; used[i] = true; path.push_back(nums[i]); dfs(nums, move(used), move(path), ans); path.pop_back(); used[i] = false; } } };

Permutations in Java:

class Solution { public List<List<Integer>> permute(int[] nums) { List<List<Integer>> ans = new ArrayList<>(); dfs(nums, new boolean[nums.length], new ArrayList<>(), ans); return ans; } private void dfs(int[] nums, boolean[] used, List<Integer> path, List<List<Integer>> ans) { if (path.size() == nums.length) { ans.add(new ArrayList<>(path)); return; } for (int i = 0; i < nums.length; ++i) { if (used[i]) continue; used[i] = true; path.add(nums[i]); dfs(nums, used, path, ans); path.remove(path.size() - 1); used[i] = false; } } }

Permutations in Python:

class Solution: def permute(self, nums: List[int]) -> List[List[int]]: ans = [] used = [False] * len(nums) def dfs(path: List[int]) -> None: if len(path) == len(nums): ans.append(path) return for i in range(len(nums)): if used[i]: continue used[i] = True dfs(path + [nums[i]]) used[i] = False dfs([]) return ans

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