Mark and Toys in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

  • It is easy to understand.
  • Algorithm is a step-wise representation of a solution to a given problem.
  • In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the Problem Mark and Toys – Hacker Rank Solution

Mark and Toys – Hacker Rank Solution

Problem:

Mark and Jane are very happy after having their first child. Their son loves toys, so Mark wants to buy some. There are a number of different toys lying in front of him, tagged with their prices. Mark has only a certain amount to spend, and he wants to maximize the number of toys he buys with this money. Given a list of toy prices and an amount to spend, determine the maximum number of gifts he can buy.

Note Each toy can be purchased only once.

Example

The budget is  units of currency. He can buy items that cost  for , or  for  units. The maximum is  items.

Function Description

Complete the function maximumToys in the editor below.

maximumToys has the following parameter(s):

  • int prices[n]: the toy prices
  • int k: Mark’s budget

Returns

  • int: the maximum number of toys

Input Format

The first line contains two integers,  and , the number of priced toys and the amount Mark has to spend.
The next line contains  space-separated integers 

Constraints




A toy can’t be bought multiple times.

Sample Input

7 50
1 12 5 111 200 1000 10

Sample Output

4

Explanation

He can buy only  toys at most. These toys have the following prices: 1,12,5,10.

Mark and Toys – Hacker Rank Solution
import java.util.Arrays;
import java.util.Scanner;

/**
 * @author Techno-RJ
 *
 */
public class MarkAndToys {
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int n = in.nextInt();
		int K = in.nextInt();
		int a[] = new int[n];
		for (int i = 0; i < n; i++) {
			a[i] = in.nextInt();
		}
		Arrays.sort(a);
		int toyCount = 0, sum = 0;
		for (int i = 0; i < a.length; i++) {
			sum += a[i];
			if (sum <= K) {
				toyCount++;
			} else {
				break;
			}
		}
		System.out.println(toyCount);
		in.close();
	}
}

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