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In this post, you will find the solution for the **Minimum Depth of Binary Tree** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Minimum Depth of Binary Tree– LeetCode Problem

Minimum Depth of Binary Tree– LeetCode Problem

**Problem:**

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

**Note:** A leaf is a node with no children.

**Example 1:**

Input:root = [3,9,20,null,null,15,7]Output:2

**Example 2:**

Input:root = [2,null,3,null,4,null,5,null,6]Output:5

**Constraints:**

- The number of nodes in the tree is in the range
`[0, 10`

.^{5}] `-1000 <= Node.val <= 1000`

Minimum Depth of Binary Tree– LeetCode Solutions

Minimum Depth of Binary Tree Solution in C++:

class Solution { public: int minDepth(TreeNode* root) { if (!root) return 0; int ans = 0; queue<TreeNode*> q{{root}}; while (!q.empty()) { ++ans; for (int size = q.size(); size > 0; --size) { TreeNode* node = q.front(); q.pop(); if (!node->left && !node->right) return ans; if (node->left) q.push(node->left); if (node->right) q.push(node->right); } } throw; } };

Minimum Depth of Binary Tree Solution in Java:

class Solution { public int minDepth(TreeNode root) { if (root == null) return 0; if (root.left == null) return minDepth(root.right) + 1; if (root.right == null) return minDepth(root.left) + 1; return Math.min(minDepth(root.left), minDepth(root.right)) + 1; } }

Minimum Depth of Binary Tree Solution in Python:

class Solution: def minDepth(self, root: Optional[TreeNode]) -> int: if not root: return 0 if not root.left: return self.minDepth(root.right) + 1 if not root.right: return self.minDepth(root.left) + 1 return min(self.minDepth(root.left), self.minDepth(root.right)) + 1