Multiply Strings LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Multiply Strings in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

Use “Ctrl+F” To Find Any Questions Answer. & For Mobile User, You Just Need To Click On Three dots In Your Browser & You Will Get A “Find” Option There. Use These Option to Get Any Random Questions Answer.

About LeetCode

LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews. 

LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either EasyMedium, or Hard.

LeetCode problems focus on algorithms and data structures. Here is some topic you can find problems on LeetCode:

  • Mathematics/Basic Logical Based Questions
  • Arrays
  • Strings
  • Hash Table
  • Dynamic Programming
  • Stack & Queue
  • Trees & Graphs
  • Greedy Algorithms
  • Breadth-First Search
  • Depth-First Search
  • Sorting & Searching
  • BST (Binary Search Tree)
  • Database
  • Linked List
  • Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the ProblemMultiply Strings– LeetCode Problem

Multiply Strings – LeetCode Problem


Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string.

Note: You must not use any built-in BigInteger library or convert the inputs to integer directly.

Example 1:

Input: num1 = "2", num2 = "3"
Output: "6"

Example 2:

Input: num1 = "123", num2 = "456"
Output: "56088"


  • 1 <= num1.length, num2.length <= 200
  • num1 and num2 consist of digits only.
  • Both num1 and num2 do not contain any leading zero, except the number 0 itself.
Multiply Strings– LeetCode Solutions
Multiply Strings in C++:
class Solution {
  string multiply(string num1, string num2) {
    string s(num1.length() + num2.length(), '0');

    for (int i = num1.length() - 1; i >= 0; --i)
      for (int j = num2.length() - 1; j >= 0; --j) {
        const int mult = (num1[i] - '0') * (num2[j] - '0');
        const int sum = mult + (s[i + j + 1] - '0');
        s[i + j] += sum / 10;
        s[i + j + 1] = '0' + sum % 10;

    const int i = s.find_first_not_of('0');
    return i == -1 ? "0" : s.substr(i);
Multiply Strings in Java:
class Solution {
  public String multiply(String num1, String num2) {
    final int m = num1.length();
    final int n = num2.length();

    StringBuilder sb = new StringBuilder();
    int[] pos = new int[m + n];

    for (int i = m - 1; i >= 0; --i)
      for (int j = n - 1; j >= 0; --j) {
        final int multiply = (num1.charAt(i) - '0') * (num2.charAt(j) - '0');
        final int sum = multiply + pos[i + j + 1];
        pos[i + j] += sum / 10;
        pos[i + j + 1] = sum % 10;

    for (final int p : pos)
      if (p > 0 || sb.length() > 0)

    return sb.length() == 0 ? "0" : sb.toString();
Multiply Strings in Python:
class Solution:
  def multiply(self, num1: str, num2: str) -> str:
    s = [0] * (len(num1) + len(num2))

    for i in range(len(num1) - 1, -1, -1):
      for j in range(len(num2) - 1, -1, -1):
        mult = int(num1[i]) * int(num2[j])
        summ = mult + s[i + j + 1]
        s[i + j] += summ // 10
        s[i + j + 1] = summ % 10

    for i, c in enumerate(s):
      if c != 0:

    return ''.join(map(str, s[i:]))

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