LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Problems C++
Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.
In this post, you will find the solution for the Trapping Rain Water in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.
Use “Ctrl+F” To Find Any Questions Answer. & For Mobile User, You Just Need To Click On Three dots In Your Browser & You Will Get A “Find” Option There. Use These Option to Get Any Random Questions Answer.
About LeetCode
LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews.
LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.
LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either Easy, Medium, or Hard.
LeetCode problems focus on algorithms and data structures. Here is some topic you can find problems on LeetCode:
- Mathematics/Basic Logical Based Questions
- Arrays
- Strings
- Hash Table
- Dynamic Programming
- Stack & Queue
- Trees & Graphs
- Greedy Algorithms
- Breadth-First Search
- Depth-First Search
- Sorting & Searching
- BST (Binary Search Tree)
- Database
- Linked List
- Recursion, etc.
Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.
Link for the Problem – Trapping Rain Water– LeetCode Problem
Trapping Rain Water– LeetCode Problem
Problem:
Given n
non-negative integers representing an elevation map where the width of each bar is 1
, compute how much water it can trap after raining.
Example 1:
![Trapping Rain Water LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct] 2 rainwatertrap](https://assets.leetcode.com/uploads/2018/10/22/rainwatertrap.png)
Input: height = [0,1,0,2,1,0,1,3,2,1,2,1] Output: 6 Explanation: The above elevation map (black section) is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped.
Example 2:
Input: height = [4,2,0,3,2,5] Output: 9
Constraints:
n == height.length
1 <= n <= 2 * 104
0 <= height[i] <= 105
Trapping Rain Water– LeetCode Solutions
class Solution { public: int trap(vector<int>& height) { if (height.empty()) return 0; int ans = 0; int l = 0; int r = height.size() - 1; int maxL = height[l]; int maxR = height[r]; while (l < r) if (maxL < maxR) { ans += maxL - height[l]; maxL = max(maxL, height[++l]); } else { ans += maxR - height[r]; maxR = max(maxR, height[--r]); } return ans; } };
class Solution { public int trap(int[] height) { if (height.length == 0) return 0; int ans = 0; int l = 0; int r = height.length - 1; int maxL = height[l]; int maxR = height[r]; while (l < r) if (maxL < maxR) { ans += maxL - height[l]; maxL = Math.max(maxL, height[++l]); } else { ans += maxR - height[r]; maxR = Math.max(maxR, height[--r]); } return ans; } }
class Solution: def trap(self, height: List[int]) -> int: if not height: return 0 ans = 0 l = 0 r = len(height) - 1 maxL = height[l] maxR = height[r] while l < r: if maxL < maxR: ans += maxL - height[l] l += 1 maxL = max(maxL, height[l]) else: ans += maxR - height[r] r -= 1 maxR = max(maxR, height[r]) return ans
tadalafil 20mg over the counter cialis online erection pills online
order cefadroxil 500mg sale buy epivir online proscar canada
buy generic estrace buy lamictal cheap prazosin 1mg uk
fluconazole 200mg price cipro 1000mg generic cipro medication
buy generic mebendazole for sale buy vermox 100mg online tadalis 10mg without prescription
metronidazole 200mg ca order keflex 250mg generic cephalexin 125mg over the counter
buy generic avanafil brand diclofenac 100mg cambia sale
buy cleocin 150mg generic cheap erectile dysfunction pills online order generic fildena
nolvadex 20mg canada order nolvadex 20mg generic ceftin 250mg pills
order trimox pill generic biaxin 250mg clarithromycin online buy
buy generic careprost buy trazodone no prescription order desyrel 50mg generic
where to buy minocin without a prescription minomycin oral cost pioglitazone 30mg
leflunomide price azulfidine over the counter buy azulfidine 500 mg online cheap
order tadalafil 10mg female viagra liquid cialis
azipro generic buy omnacortil 20mg generic gabapentin 100mg pills
ivermectin 50ml buy erectile dysfunction drugs over the counter cheap deltasone
furosemide 40mg canada doxycycline generic ventolin order online
ramipril 5mg pills generic ramipril order arcoxia generic
vardenafil online buy buy generic tizanidine over the counter buy plaquenil 200mg generic
order asacol 800mg generic irbesartan 300mg cheap brand avapro 150mg
buy vardenafil 20mg sale order vardenafil online order hydroxychloroquine 400mg pills