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In this post, you will find the solution for the **Remove Linked List Elements in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Remove Linked List Elements– LeetCode Problem

Remove Linked List Elements– LeetCode Problem

**Problem:**

Given the `head`

of a linked list and an integer `val`

, remove all the nodes of the linked list that has `Node.val == val`

, and return *the new head*.

**Example 1:**

Input:head = [1,2,6,3,4,5,6], val = 6Output:[1,2,3,4,5]

**Example 2:**

Input:head = [], val = 1Output:[]

**Example 3:**

Input:head = [7,7,7,7], val = 7Output:[]

**Constraints:**

- The number of nodes in the list is in the range
`[0, 10`

.^{4}] `1 <= Node.val <= 50`

`0 <= val <= 50`

Remove Linked List Elements– LeetCode Solutions

Remove Linked List ElementsSolution in C++:

class Solution { public: ListNode* removeElements(ListNode* head, int val) { ListNode dummy(0, head); ListNode* prev = &dummy; for (; head; head = head->next) if (head->val != val) { prev->next = head; prev = prev->next; } prev->next = nullptr; // in case the last val == val return dummy.next; } };

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Remove Linked List ElementsSolution in Java:

class Solution { public ListNode removeElements(ListNode head, int val) { ListNode dummy = new ListNode(0, head); ListNode prev = dummy; for (; head != null; head = head.next) if (head.val != val) { prev.next = head; prev = prev.next; } prev.next = null; // in case the last val == val return dummy.next; } }

Remove Linked List ElementsSolution in Python:

class Solution: def removeElements(self, head: ListNode, val: int) -> ListNode: dummy = ListNode(0, head) prev = dummy while head: if head.val != val: prev.next = head prev = prev.next head = head.next prev.next = None return dummy.next

**Time:**O(n)**Space:**O(1)