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In this post, you will find the solution for the **Reverse Integer** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Reverse Integer– LeetCode Problem

Reverse Integer– LeetCode Problem

**Problem:**

Given a signed 32-bit integer `x`

, return `x`

* with its digits reversed*. If reversing `x`

causes the value to go outside the signed 32-bit integer range `[-2`

, then return ^{31}, 2^{31} - 1]`0`

.

**Assume the environment does not allow you to store 64-bit integers (signed or unsigned).**

**Example 1:**

Input:x = 123Output:321

**Example 2:**

Input:x = -123Output:-321

**Example 3:**

Input:x = 120Output:21

**Constraints:**

`-2`

^{31}<= x <= 2^{31}- 1

Reverse Integer– LeetCode Solutions

class Solution { public: int reverse(int x) { long ans = 0; while (x) { ans = ans * 10 + x % 10; x /= 10; } return (ans < INT_MIN || ans > INT_MAX) ? 0 : ans; } };

class Solution { public int reverse(int x) { long ans = 0; while (x != 0) { ans = ans * 10 + x % 10; x /= 10; } return (ans < Integer.MIN_VALUE || ans > Integer.MAX_VALUE) ? 0 : (int) ans; } }

class Solution: def reverse(self, x: int) -> int: ans = 0 sign = -1 if x < 0 else 1 x *= sign while x: ans = ans * 10 + x % 10 x //= 10 return 0 if ans < -2**31 or ans > 2**31 - 1 else sign * ans