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Link for the Problem – String to Integer (atoi)– LeetCode Problem
String to Integer (atoi)– LeetCode Problem
Problem:
Implement the myAtoi(string s)
function, which converts a string to a 32-bit signed integer (similar to C/C++’s atoi
function).
The algorithm for myAtoi(string s)
is as follows:
- Read in and ignore any leading whitespace.
- Check if the next character (if not already at the end of the string) is
'-'
or'+'
. Read this character in if it is either. This determines if the final result is negative or positive respectively. Assume the result is positive if neither is present. - Read in next the characters until the next non-digit character or the end of the input is reached. The rest of the string is ignored.
- Convert these digits into an integer (i.e.
"123" -> 123
,"0032" -> 32
). If no digits were read, then the integer is0
. Change the sign as necessary (from step 2). - If the integer is out of the 32-bit signed integer range
[-231, 231 - 1]
, then clamp the integer so that it remains in the range. Specifically, integers less than-231
should be clamped to-231
, and integers greater than231 - 1
should be clamped to231 - 1
. - Return the integer as the final result.
Note:
- Only the space character
' '
is considered a whitespace character. - Do not ignore any characters other than the leading whitespace or the rest of the string after the digits.
Example 1:
Input: s = "42" Output: 42 Explanation: The underlined characters are what is read in, the caret is the current reader position. Step 1: "42" (no characters read because there is no leading whitespace) ^ Step 2: "42" (no characters read because there is neither a '-' nor '+') ^ Step 3: "42" ("42" is read in) ^ The parsed integer is 42. Since 42 is in the range [-231, 231 - 1], the final result is 42.
Example 2:
Input: s = " -42" Output: -42 Explanation: Step 1: " -42" (leading whitespace is read and ignored) ^ Step 2: " -42" ('-' is read, so the result should be negative) ^ Step 3: " -42" ("42" is read in) ^ The parsed integer is -42. Since -42 is in the range [-231, 231 - 1], the final result is -42.
Example 3:
Input: s = "4193 with words" Output: 4193 Explanation: Step 1: "4193 with words" (no characters read because there is no leading whitespace) ^ Step 2: "4193 with words" (no characters read because there is neither a '-' nor '+') ^ Step 3: "4193 with words" ("4193" is read in; reading stops because the next character is a non-digit) ^ The parsed integer is 4193. Since 4193 is in the range [-231, 231 - 1], the final result is 4193.
Constraints:
0 <= s.length <= 200
s
consists of English letters (lower-case and upper-case), digits (0-9
),' '
,'+'
,'-'
, and'.'
.
String to Integer (atoi)– LeetCode Solutions
class Solution { public: int myAtoi(string s) { trim(s); if (s.empty()) return 0; const int sign = s[0] == '-' ? -1 : 1; if (s[0] == '+' || s[0] == '-') s = s.substr(1); long num = 0; for (const char c : s) { if (!isdigit(c)) break; num = num * 10 + (c - '0'); if (sign * num < INT_MIN) return INT_MIN; if (sign * num > INT_MAX) return INT_MAX; } return sign * num; } private: void trim(string& s) { s.erase(0, s.find_first_not_of(' ')); s.erase(s.find_last_not_of(' ') + 1); } };
class Solution { public int myAtoi(String s) { s = s.strip(); if (s.isEmpty()) return 0; final int sign = s.charAt(0) == '-' ? -1 : 1; if (s.charAt(0) == '+' || s.charAt(0) == '-') s = s.substring(1); long num = 0; for (final char c : s.toCharArray()) { if (!Character.isDigit(c)) break; num = num * 10 + (c - '0'); if (sign * num <= Integer.MIN_VALUE) return Integer.MIN_VALUE; if (sign * num >= Integer.MAX_VALUE) return Integer.MAX_VALUE; } return sign * (int) num; } }
class Solution: def myAtoi(self, s: str) -> int: s = s.strip() if not s: return 0 sign = -1 if s[0] == '-' else 1 if s[0] in {'-', '+'}: s = s[1:] num = 0 for c in s: if not c.isdigit(): break num = num * 10 + ord(c) - ord('0') if sign * num <= -2**31: return -2**31 if sign * num >= 2**31 - 1: return 2**31 - 1 return sign * num
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