Set .intersection() Operation in python | HackerRank Programming Solutions | HackerRank Python Solutions

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Python Hackerrank Solutions

Hello Programmers/Coders, Today we are going to share solutions of Programming problems of HackerRank of Programming Language Python. At Each Problem with Successful submission with all Test Cases Passed, you will get an score or marks. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

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Introduction To Python

Python is a widely-used, interpreted, object-oriented, and high-level programming language with dynamic semantics, used for general-purpose programming. It was created by Guido van Rossum, and first released on February 20, 1991.

Python is a computer programming language often used to build websites and software, automate tasks, and conduct data analysis. It is also used to create various machine learning algorithm, and helps in Artificial Intelligence. Python is a general purpose language, meaning it can be used to create a variety of different programs and isn’t specialized for any specific problems. This versatility, along with its beginner-friendliness, has made it one of the most-used programming languages today. A survey conducted by industry analyst firm RedMonk found that it was the most popular programming language among developers in 2020.

Link for the Problem – Set .intersection() Operation in python – HackerRank Solution

Set .intersection() Operation in python – HackerRank Solution

1437830945 a56a63892c AB .intersection()

The .intersection() operator returns the intersection of a set and the set of elements in an iterable.
Sometimes, the & operator is used in place of the .intersection() operator, but it only operates on the set of elements in set.
The set is immutable to the .intersection() operation (or & operation).

>>> s = set("Hacker")
>>> print s.intersection("Rank")
set(['a', 'k'])

>>> print s.intersection(set(['R', 'a', 'n', 'k']))
set(['a', 'k'])

>>> print s.intersection(['R', 'a', 'n', 'k'])
set(['a', 'k'])

>>> print s.intersection(enumerate(['R', 'a', 'n', 'k']))
set([])

>>> print s.intersection({"Rank":1})
set([])

>>> s & set("Rank")
set(['a', 'k'])

Task

The students of District College have subscriptions to English and French newspapers. Some students have subscribed only to English, some have subscribed only to French, and some have subscribed to both newspapers.

You are given two sets of student roll numbers. One set has subscribed to the English newspaper, one set has subscribed to the French newspaper. Your task is to find the total number of students who have subscribed to both newspapers.

Input Format

The first line contains , the number of students who have subscribed to the English newspaper.
The second line contains  space separated roll numbers of those students.
The third line contains , the number of students who have subscribed to the French newspaper.
The fourth line contains  space separated roll numbers of those students.

Constraints

Output Format

Output the total number of students who have subscriptions to both English and French newspapers.

Sample Input

9
1 2 3 4 5 6 7 8 9
9
10 1 2 3 11 21 55 6 8

Sample Output

5

Explanation

The roll numbers of students who have both subscriptions:
 and .
Hence, the total is  students

Set .intersection() Operation in python – HackerRank Solution
# set.union() Operators in Python - Hacker Rank Solution
# Python 3
# Enter your code here. Read input from STDIN. Print output to STDOUT
# set.union() Operators in Python - Hacker Rank Solution START
N1 = int(input())
storage1 = set(input().split());

N2 = int(input())
storage2 = set(input().split());

storage3 = storage1.union(storage2)

print(len(storage3))
# set.union() Operators in Python - Hacker Rank Solution END

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