**LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Solutions in C++**

Hello **Programmers/Coders,** Today we are going to share ** solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python**. At Each Problem with Successful submission with

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In this post, you will find the solution for the **Add Binary** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Add Binary– LeetCode Problem

Add Binary– LeetCode Problem

**Problem:**

Given two binary strings `a`

and `b`

, return *their sum as a binary string*.

**Example 1:**

Input:a = "11", b = "1"Output:"100"

**Example 2:**

Input:a = "1010", b = "1011"Output:"10101"

**Constraints:**

`1 <= a.length, b.length <= 10`

^{4}`a`

and`b`

consist only of`'0'`

or`'1'`

characters.- Each string does not contain leading zeros except for the zero itself.

**Add Binary– LeetCode Solutions**

Add Binary in C++:

class Solution { public: string addBinary(string a, string b) { string ans; int carry = 0; int i = a.length() - 1; int j = b.length() - 1; while (i >= 0 || j >= 0 || carry) { if (i >= 0) carry += a[i--] - '0'; if (j >= 0) carry += b[j--] - '0'; ans += carry % 2 + '0'; carry /= 2; } reverse(begin(ans), end(ans)); return ans; } };

Add Binary in Java:

class Solution { public String addBinary(String a, String b) { StringBuilder sb = new StringBuilder(); int carry = 0; int i = a.length() - 1; int j = b.length() - 1; while (i >= 0 || j >= 0 || carry == 1) { if (i >= 0) carry += a.charAt(i--) - '0'; if (j >= 0) carry += b.charAt(j--) - '0'; sb.append(carry % 2); carry /= 2; } return sb.reverse().toString(); } }

Add Binary in Python:

class Solution: def addBinary(self, a: str, b: str) -> str: s = [] carry = 0 i = len(a) - 1 j = len(b) - 1 while i >= 0 or j >= 0 or carry: if i >= 0: carry += int(a[i]) i -= 1 if j >= 0: carry += int(b[j]) j -= 1 s.append(str(carry % 2)) carry //= 2 return ''.join(s[::-1])