Plus One LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Plus One in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the Problem – Plus One– LeetCode Problem

Plus One– LeetCode Problem

Problem:

You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0‘s.

Increment the large integer by one and return the resulting array of digits.

Example 1:

Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].

Example 2:

Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].

Example 3:

Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].

Constraints:

• 1 <= digits.length <= 100
• 0 <= digits[i] <= 9
• digits does not contain any leading 0‘s.

Plus One– LeetCode Solutions

Plus One in C++:

class Solution {
 public:
  vector<int> plusOne(vector<int>& digits) {
    for (int i = digits.size() - 1; i >= 0; --i) {
      if (digits[i] < 9) {
        ++digits[i];
        return digits;
      }
      digits[i] = 0;
    }

    digits.insert(begin(digits), 1);
    return digits;
  }
};

Plus One in Java:

class Solution {
  public int[] plusOne(int[] digits) {
    for (int i = digits.length - 1; i >= 0; i--) {
      if (digits[i] < 9) {
        ++digits[i];
        return digits;
      }
      digits[i] = 0;
    }

    int[] ans = new int[digits.length + 1];
    ans[0] = 1;
    return ans;
  }
}

Plus One in Python:

class Solution:
  def plusOne(self, digits: List[int]) -> List[int]:
    for i in range(len(digits) - 1, -1, -1):
      if digits[i] < 9:
        digits[i] += 1
        return digits
      digits[i] = 0

    return [1] + digits