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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.
In this post, you will find the solution for the Valid Number in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.
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Link for the Problem – Valid Number– LeetCode Problem
Valid Number– LeetCode Problem
Problem:
A valid number can be split up into these components (in order):
- A decimal number or an integer.
- (Optional) An
'e'
or'E'
, followed by an integer.
A decimal number can be split up into these components (in order):
- (Optional) A sign character (either
'+'
or'-'
). - One of the following formats:
- One or more digits, followed by a dot
'.'
. - One or more digits, followed by a dot
'.'
, followed by one or more digits. - A dot
'.'
, followed by one or more digits.
- One or more digits, followed by a dot
An integer can be split up into these components (in order):
- (Optional) A sign character (either
'+'
or'-'
). - One or more digits.
For example, all the following are valid numbers: ["2", "0089", "-0.1", "+3.14", "4.", "-.9", "2e10", "-90E3", "3e+7", "+6e-1", "53.5e93", "-123.456e789"]
, while the following are not valid numbers: ["abc", "1a", "1e", "e3", "99e2.5", "--6", "-+3", "95a54e53"]
.
Given a string s
, return true
if s
is a valid number.
Example 1:
Input: s = "0" Output: true
Example 2:
Input: s = "e" Output: false
Example 3:
Input: s = "." Output: false
Constraints:
1 <= s.length <= 20
s
consists of only English letters (both uppercase and lowercase), digits (0-9
), plus'+'
, minus'-'
, or dot'.'
.
Valid Number– LeetCode Solutions
Valid Number in C++:
class Solution { public: bool isNumber(string s) { trim(s); if (s.empty()) return false; bool seenNum = false; bool seenDot = false; bool seenE = false; for (int i = 0; i < s.length(); ++i) { switch (s[i]) { case '.': if (seenDot || seenE) return false; seenDot = true; break; case 'e': if (seenE || !seenNum) return false; seenE = true; seenNum = false; break; case '+': case '-': if (i > 0 && s[i - 1] != 'e') return false; seenNum = false; break; default: if (!isdigit(s[i])) return false; seenNum = true; } } return seenNum; } private: void trim(string& s) { s.erase(0, s.find_first_not_of(' ')); s.erase(s.find_last_not_of(' ') + 1); } };
Valid Number in Java:
class Solution { public boolean isNumber(String s) { s = s.trim(); if (s.isEmpty()) return false; boolean seenNum = false; boolean seenDot = false; boolean seenE = false; for (int i = 0; i < s.length(); ++i) { switch (s.charAt(i)) { case '.': if (seenDot || seenE) return false; seenDot = true; break; case 'e': if (seenE || !seenNum) return false; seenE = true; seenNum = false; break; case '+': case '-': if (i > 0 && s.charAt(i - 1) != 'e') return false; seenNum = false; break; default: if (!Character.isDigit(s.charAt(i))) return false; seenNum = true; } } return seenNum; } }
Valid Number in Python:
class Solution: def isNumber(self, s: str) -> bool: s = s.strip() if not s: return False seenNum = False seenDot = False seenE = False for i, c in enumerate(s): if c == '.': if seenDot or seenE: return False seenDot = True elif c == 'e': if seenE or not seenNum: return False seenE = True seenNum = False elif c in '+-': if i > 0 and s[i - 1] != 'e': return False seenNum = False else: if not c.isdigit(): return False seenNum = True return seenNum
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